Evaluate:
[(16)−1−(15)−1]−2\Big[\Big(\dfrac{1}{6}\Big)^{-1} - \Big(\dfrac{1}{5}\Big)^{-1}\Big]^{-2}[(61)−1−(51)−1]−2
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[(16)−1−(15)−1]−2=[61−51]−2=[6−5]−2=[1]−2=112=12=1\Big[\Big(\dfrac{1}{6}\Big)^{-1} - \Big(\dfrac{1}{5}\Big)^{-1}\Big]^{-2}\\[1em] = [6^1 - 5^1]^{-2}\\[1em] = [6 - 5]^{-2}\\[1em] = [1]^{-2}\\[1em] = \dfrac{1}{1}^2\\[1em] = 1^2\\[1em] = 1[(61)−1−(51)−1]−2=[61−51]−2=[6−5]−2=[1]−2=112=12=1
[(16)−1−(15)−1]−2=1\Big[\Big(\dfrac{1}{6}\Big)^{-1} - \Big(\dfrac{1}{5}\Big)^{-1}\Big]^{-2} = 1[(61)−1−(51)−1]−2=1
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