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Mathematics

Evaluate:

80+40+208^0 + 4^0 + 2^0

Exponents

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Answer

According to property of exponents, a0=1a^0 = 1

80+40+20=1+1+1=38^0 + 4^0 + 2^0 \\[1em] = 1 + 1 + 1 \\[1em] = 3

Hence, 80+40+20=38^0 + 4^0 + 2^0 = 3

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