Evaluate:
(−5)0(-5)^0(−5)0
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According to property of exponents, a0=1a^0 = 1a0=1
Then, (−5)0=1(-5)^0 = 1(−5)0=1
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Simplify:
[(64)−2]−3÷[{(−8)2}3]2[(64)^{-2}]^{-3} ÷ [{(-8)^2}^3]^2[(64)−2]−3÷[{(−8)2}3]2
(2−3−2−4)(2−3+2−4)(2^{-3} - 2^{-4})(2^{-3} + 2^{-4})(2−3−2−4)(2−3+2−4)
80+40+208^0 + 4^0 + 2^080+40+20
(8+4+2)0(8 + 4 + 2)^0(8+4+2)0