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Mathematics

Evaluate:

{(12)2}3\Big{\Big(-\dfrac{1}{2}\Big)^{-2}\Big}^{-3}

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Answer

{(12)2}3={(21)2}3={(2×21×1)}3={41}3={14}3={1×1×14×4×4}=164\Big{\Big(-\dfrac{1}{2}\Big)^{-2}\Big}^{-3}\\[1em] = \Big{\Big(-\dfrac{2}{1}\Big)^2\Big}^{-3}\\[1em] = \Big{\Big(-\dfrac{2 \times 2}{1 \times 1}\Big)\Big}^{-3}\\[1em] = \Big{\dfrac{4}{1}\Big}^{-3}\\[1em] = \Big{\dfrac{1}{4}\Big}^3\\[1em] = \Big{\dfrac{1 \times 1 \times 1 }{4 \times 4 \times 4}\Big}\\[1em] = \dfrac{1}{64}

{(12)2}3=164\Big{\Big(-\dfrac{1}{2}\Big)^{-2}\Big}^{-3} = \dfrac{1}{64}

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