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Mathematics

Evaluate:

[37]5×[73]2\Big[-\dfrac{3}{7}\Big]^{-5} \times \Big[\dfrac{7}{3}\Big]^2

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Answer

[37]5×[73]2=[73]5×[73]2=[7535]×[7232]=[75+235+2]=[7737]\Big[-\dfrac{3}{7}\Big]^{-5} \times \Big[\dfrac{7}{3}\Big]^2\\[1em] = \Big[-\dfrac{7}{3}\Big]^5 \times \Big[\dfrac{7}{3}\Big]^2\\[1em] = \Big[-\dfrac{7^5}{3^5}\Big] \times \Big[\dfrac{7^2}{3^2}\Big]\\[1em] = \Big[-\dfrac{7^{5+2}}{3^{5+2}}\Big]\\[1em] = \Big[-\dfrac{7^{7}}{3^{7}}\Big]

Hence,[37]5×[73]2=[7737]\Big[-\dfrac{3}{7}\Big]^{-5} \times \Big[\dfrac{7}{3}\Big]^2 = \Big[-\dfrac{7^{7}}{3^{7}}\Big].

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