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Mathematics

Evaluate (3x4y2) (2x2y3) for x = 1 and y = 2.

Algebraic Expressions

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Answer

(3x4y2) ×\times (2x2y3)

= 6x(4+2)y(2+3)

= 6x6y5

Putting x = 1 and y = 2, we get

6 x 16 x 25

= 6 x 1 x 32

= 192

Hence, (3x4y2) (2x2y3) for x = 1 and y = 2 is 192

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