Evaluate: (a + bc) (a - bc) (a^2 + b^2c^2)

(a \+ bc) (a \- bc) (a 2 \+ b 2 c 2 ) Using the formula [∵ (x \+ y)(x \- y) = x 2 \- y 2 ] = [a 2 \- (bc) 2 ] (a 2 \+ b 2 c 2 ) = (a 2 \- b 2 c 2 ) (a 2 \+ b 2 c 2 ) = (a 2 ) 2 \- (b 2 c 2 ) 2 = a 4 \- b 4 c 4 Hence, (a \+ bc) (a \- bc) (a 2 \+ b 2 c 2 ) = a 4 \- b 4 c 4

Mathematics

Evaluate:
(a + bc) (a - bc) (a² + b²c²)

Identities

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Answer

(a + bc) (a - bc) (a² + b²c²)

Using the formula

[∵ (x + y)(x - y) = x² - y²]

= [a² - (bc)²] (a² + b²c²)

= (a² - b²c²) (a² + b²c²)

= (a²)² - (b²c²)²

= a⁴ - b⁴c⁴

Hence, (a + bc) (a - bc) (a² + b²c²) = a⁴ - b⁴c⁴

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Mathematics

Evaluate:
(a + bc) (a - bc) (a² + b²c²)

Identities

Answer

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(2a + 3) (2a - 3) (4a² + 9)

Mathematics

Evaluate:(a + bc) (a - bc) (a2 + b2c2)

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Evaluate:
(a + bc) (a - bc) (a² + b²c²)

Evaluate:
(2a + 3) (2a - 3) (4a² + 9)