Evaluate the following :
(9)52−3×(4)0−(181)−12(9)^{\dfrac{5}{2}} - 3 \times (4)^0 - \Big(\dfrac{1}{81}\Big)^{-\dfrac{1}{2}}(9)25−3×(4)0−(811)−21
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Given,
Simplifying the expression :
⇒(9)52−3(4)0−(181)−12⇒[(3)2]52−3(1)−(81)12⇒35−3−(92)12⇒(3)5−3−9⇒243−3−9⇒231.\Rightarrow (9)^{\dfrac{5}{2}} - 3(4)^0 - \Big(\dfrac{1}{81}\Big)^{-\dfrac{1}{2}} \\[1em] \Rightarrow [(3)^2]^{\dfrac{5}{2}} - 3(1) - (81)^\dfrac{1}{2} \\[1em] \Rightarrow 3^5 - 3 - (9^2)^{\dfrac{1}{2}} \\[1em] \Rightarrow (3)^5 - 3 - 9 \\[1em] \Rightarrow 243 - 3 - 9 \\[1em] \Rightarrow 231.⇒(9)25−3(4)0−(811)−21⇒[(3)2]25−3(1)−(81)21⇒35−3−(92)21⇒(3)5−3−9⇒243−3−9⇒231.
Hence, (9)52−3.(4)0−(181)−12=231(9)^{\dfrac{5}{2}} - 3.(4)^0 - \Big(\dfrac{1}{81}\Big)^{-\dfrac{1}{2}} = 231(9)25−3.(4)0−(811)−21=231.
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Simplify :
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