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Mathematics

Evaluate :

logb a × logc b × loga c

Logarithms

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Answer

Simplifying the expression,

logba×logcb×logaclog alog b×log blog c×log clog alog a.log b.log clog b.log c.log a1.\Rightarrow \text{log}b a \times \text{log}c b \times \text{log}_a c \\[1em] \Rightarrow \dfrac{\text{log a}}{\text{log b}} \times \dfrac{\text{log b}}{\text{log c}} \times \dfrac{\text{log c}}{\text{log a}} \\[1em] \Rightarrow \dfrac{\text{log a.log b.log c}}{\text{log b.log c.log a}} \\[1em] \Rightarrow 1.

Hence, logb a × logc b × loga c = 1.

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