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(a + b - c)2
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Answer
(a + b - c)2
Using the formula,
[∵ (x + y - z)2 = x2 + y2 + z2 + 2xy - 2yz - 2xz]
= a2 + b2 + c2 + 2ab - 2bc - 2ca
Hence, (a + b - c)2 = a2 + b2 + c2 + 2ab - 2bc - 2ca
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Expand:
(a + b - c)2
4 Likes
(a + b - c)2
Using the formula,
[∵ (x + y - z)2 = x2 + y2 + z2 + 2xy - 2yz - 2xz]
= a2 + b2 + c2 + 2ab - 2bc - 2ca
Hence, (a + b - c)2 = a2 + b2 + c2 + 2ab - 2bc - 2ca
Answered By
3 Likes