Express cosec 68° + cot 72° in terms of angles between 0° and 45°.
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Solving,
⇒ cosec 68° + cot 72°
⇒ cosec (90 - 22)° + cot (90 - 18)°
By formula,
cosec (90° - A) = sec A and cot (90° - A) = tan A.
⇒ sec 22° + tan 18°.
Hence, cosec 68° + cot 72° = sec 22° + tan 18°.
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Show that :
sin 42° sec 48° + cos 42° cosec 48° = 2
Express sin 59° + tan 63° in terms of angles between 0° and 45°.