Express the following in terms of angles between 0° and 45° :
cosec 68° + cot 72°
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cosec 68°+ cot 72°
= cosec (90° - 22°) + cot (90° - 18°)
= sec 22° + tan 18°
Hence, cosec 68°+ cot 72° = sec 22° + tan 18°.
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Show that :
sin 42° sec 48° + cos 42° cosec 48° = 2
sin 59° + tan 63°
cos 74° + sec 67°