Express the following in a form free from logarithm :
2 log x + 3 log y = log a
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Given,
⇒ 2 log x + 3 log y = log a
⇒ log x2 + log y3 = log a
⇒ log (x2.y3) = log a
⇒ x2.y3 = a
Hence, required equation is x2y3 = a.
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2 log x - log y = 1
a log x - b log y = 2 log 3
Evaluate :
log 5 + log 8 - 2 log 2