The expression equivalent to sec2 θ + cosec2 θ is : 1. sec2 θ · cosec2 θ 2. tan2 θ + cot2 θ 3. 4. 2 sec2 θ + 1

sec2 θ + cosec2 θ Hence, option 1 is the correct option.

Mathematics

The expression equivalent to sec² θ + cosec² θ is :
sec² θ · cosec² θ
tan² θ + cot² θ
$\dfrac{1}{\sec^2 θ \times \cosec^2 θ}$
2 sec² θ + 1

Trigonometric Identities

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Answer

sec² θ + cosec² θ

$\Rightarrow \dfrac{1}{\cos^2 \theta} + \dfrac{1}{\sin^2 \theta} \\[1em] \Rightarrow \dfrac{\sin^2 \theta + \cos^2 \theta}{\cos^2 \theta\sin^2 \theta} \\[1em] \Rightarrow \dfrac{1}{\cos^2 \theta\sin^2 \theta} \\[1em] \Rightarrow \sec^2 \theta (\cosec^2 \theta)$

Hence, option 1 is the correct option.

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Mathematics

The expression equivalent to sec² θ + cosec² θ is :
sec² θ · cosec² θ
tan² θ + cot² θ
$\dfrac{1}{\sec^2 θ \times \cosec^2 θ}$
2 sec² θ + 1

Trigonometric Identities

Answer

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Mathematics

The expression equivalent to sec2 θ + cosec2 θ is :sec2 θ · cosec2 θtan2 θ + cot2 θ1sec⁡2θ×cosec⁡2θ\dfrac{1}{\sec^2 θ \times \cosec^2 θ}sec2θ×cosec2θ1​2 sec2 θ + 1

Trigonometric Identities

Answer

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The expression equivalent to sec² θ + cosec² θ is :
sec² θ · cosec² θ
tan² θ + cot² θ
$\dfrac{1}{\sec^2 θ \times \cosec^2 θ}$
2 sec² θ + 1

If sin θ − cos θ = 0, then the value of (sin⁴ θ + cos⁴ θ) is :
$\dfrac{1}{4}$
$\dfrac{1}{2}$
$\dfrac{3}{4}$
1

If a cot θ + b cosec θ = p and b cot θ + a cosec θ = q, then p² − q² is equal to :
a² − b²
b² − a²
a² + b²
b − a

If x = a cos³ θ and y = b sin³ θ, then $\Big(\dfrac{x}{a}\Big)^{\dfrac{2}{3}} + \Big(\dfrac{y}{b}\Big)^{\dfrac{2}{3}}$ is equal to :
a
b
1
2

If sin θ + cosec θ = 2, then sin³ θ + cosec³ θ is equal to :
2
2 sin θ
−2 sin θ
2 cos θ