Mathematics
The external dimensions of a closed wooden box are 27 cm, 19 cm and 11 cm. If the thickness of the wood in the box is 1.5 cm; find :
(i) volume of the wood in the box;
(ii) the cost of the box, if wood costs ₹ 1.20 per cm3;
(iii) number of 4 cm cubes that could be placed into the box.
Mensuration
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Answer
(i) Given:
External dimensions of wooden box = 27 cm, 19 cm and 11 cm.
Thickness of the wood = 1.5 cm
External volume of box = l x b x h
= 27 x 19 x 11
= 5,643 cm 3
Internal volume of box = l x b x h
= (27 - 2 x 1.5) x (19 - 2 x 1.5) x (11 - 2 x 1.5)
= (27 - 3) x (19 - 3) x (11 - 3)
= 24 x 16 x 8
= 3,072 cm 3
Volume of wood = External volume of box - Internal volume of box
= 5,643 cm 3 - 3,072 cm 3
= 2,571 cm 3
Hence, volume of wood in the box is 2,571 cm 3.
(ii) Cost of wood = ₹ 1.20 per cm3
Total cost = Volume of wood x Cost of wood
= ₹ 2,571 x 1.20
= ₹ 3,085.20
Hence, total cost of the box is ₹ 3,085.20.
(iii) Side of cube = 4 cm
Let n be the number of cubes.
Internal volume of box = Number of cubes x Volume of cube
⇒ 3,072 = n x side3
⇒ 3,072 = n x 43
⇒ 3,072 = n x 64
⇒ n =
⇒ n = 48
Hence, the number of 4 cm cubes that could be placed into the box is 48.
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