Mathematics
Factorisation of 63x2 - 112y2 is
63(x - 2y)(x + 2y)
7(3x + 2y)(3x - 2y)
7(3x + 4y)(3x - 4y)
none of these
Factorisation
16 Likes
Answer
63x2 - 112y2 = 7[9x2 - 16y2] = 7[(3x)2 - (4y)2].
We know that,
a2 - b2 = (a + b)(a - b).
∴ 7[(3x)2 - (4y)2] = 7(3x + 4y)(3x - 4y).
Hence, Option 3 is the correct option.
Answered By
7 Likes
Related Questions
Factorisation of y(y - z) + 9(z - y) is
(y - z)(y + 9)
(y - z)(y - 9)
(z - y)(y + 9)
none of these
Factorisation of (lm + l) + m + 1 is
(lm + 1)(m + l)
(lm + m)(l + 1)
l(m + 1)
(l + 1)(m + 1)
Factorisation of p4 - 81 is
(p2 - 9)(p2 + 9)
(p - 3)(p + 3)(p2 + 9)
(p - 3)2(p + 3)2
none of these
One of the factors of (25x2 - 1) + (1 + 5x)2 is
5 + x
5 - x
5x - 1
10x