Mathematics
Factorisation of (lm + l) + m + 1 is
(lm + 1)(m + l)
(lm + m)(l + 1)
l(m + 1)
(l + 1)(m + 1)
Factorisation
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Answer
(lm + l) + m + 1
Rearranging the above terms we get,
lm + m + l + 1 = m(l + 1) + 1(l + 1)
= (l + 1)(m + 1).
Hence, Option 4 is the correct option.
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