Factorise:
(a + 4)2 - 5ab - 20b - 6b2
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Given,
⇒ (a + 4)2 - 5ab - 20b - 6b2
⇒ (a + 4)2 - 5b(a + 4) - 6b2
⇒ (a + 4)2 - 6b(a + 4) + b(a + 4) - 6b2
⇒ (a + 4)[(a + 4) - 6b] + b[(a + 4) - 6b]
⇒ (a + 4 + b)(a + 4 - 6b).
Hence, (a + 4)2 - 5ab - 20b - 6b2 = (a + 4 + b)(a + 4 - 6b).
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