Mathematics
Factorise:
8(a - 2b)2 - 2a + 4b - 1
Factorisation
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Answer
Given,
⇒ 8(a - 2b)2 - 2a + 4b - 1
⇒ 8(a - 2b)2 - 2(a - 2b) - 1
⇒ 8(a - 2b)2 - 4(a - 2b) + 2(a - 2b ) - 1
⇒ 4(a - 2b)[2(a - 2b) - 1] + 1[2(a - 2b) - 1]
⇒ [4(a - 2b) + 1][2(a - 2b) - 1]
⇒ (4a - 8b + 1)(2a - 4b - 1).
Hence, 8(a - 2b)2 - 2a + 4b - 1 = (4a - 8b + 1)(2a - 4b - 1).
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