Factorise : ax^2 + b^2y - ab^2 - x^2y

ax 2 \+ b 2 y \- ab 2 \- x 2 y = (ax 2 \- ab 2 ) \+ (b 2 y \- x 2 y) = a (x 2 \- b 2 ) \+ y(b 2 \- x 2 ) = a (x 2 \- b 2 ) \- y(x 2 \- b 2 ) = (x 2 \- b 2 )(a \- y) Using the formula [∵ (x 2 \- y 2 ) = (x \+ y)(x \- y)] = (x \- b)(x \+ b)(a \- y) Hence,ax 2 \+ b 2 y \- ab 2 \- x 2 y = (x \- b)(x \+ b)(a \- y)

Mathematics

Factorise :
ax² + b²y - ab² - x²y

Factorisation

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Answer

ax² + b²y - ab² - x²y

= (ax² - ab²) + (b²y - x²y)

= a (x² - b²) + y(b² - x²)

= a (x² - b²) - y(x² - b²)

= (x² - b²)(a - y)

Using the formula

[∵ (x² - y²) = (x + y)(x - y)]

= (x - b)(x + b)(a - y)

Hence,ax² + b²y - ab² - x²y = (x - b)(x + b)(a - y)

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Mathematics

Factorise :
ax² + b²y - ab² - x²y

Factorisation

Answer

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Factorise :ax2 + b2y - ab2 - x2y

Factorisation

Answer

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