Factorise :
b(c - d)2 + a(d - c) + 3(c - d)
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= b(c - d)2 - a(c - d) + 3(c - d)
= (c - d)(b(c - d) - a + 3)
= (c - d)(bc - bd - a + 3)
Hence,b(c - d)2 + a(d - c) + 3(c - d) = (c - d)(bc - bd - a + 3)
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