Factorise by grouping method : a 4 - 2a 3 - 4a + 8.

Given, a 4 - 2a 3 - 4a + 8 = a 4 - 4a - 2a 3 + 8 = a(a 3 - 4) - 2(a 3 - 4) = (a - 2)(a 3 - 4). Hence, a 4 - 2a 3 - 4a + 8 = (a - 2)(a 3 - 4).

Mathematics

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Given,

a⁴ - 2a³ - 4a + 8

= a⁴ - 4a - 2a³ + 8

= a(a³ - 4) - 2(a³ - 4)

= (a - 2)(a³ - 4).

Hence, a⁴ - 2a³ - 4a + 8 = (a - 2)(a³ - 4).

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