Mathematics
Factorise by grouping method :
16(a + b)2 - 4a - 4b
Factorisation
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Answer
Given,
16(a + b)2 - 4a - 4b
= 16(a + b)2 - 4(a + b)
= 4(a + b)[4(a + b) - 1]
= 4(a + b)[4a + 4b - 1]
= 4(a + b)(4a + 4b - 1).
Hence, 16(a + b)2 - 4a - 4b = 4(a + b)(4a + 4b - 1).
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