Mathematics
Factorise by taking out the common factors :
xy(3x2 - 2y2) - yz(2y2 - 3x2) + zx(15x2 - 10y2)
Factorisation
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Answer
Given,
xy(3x2 - 2y2) - yz(2y2 - 3x2) + zx(15x2 - 10y2)
= xy(3x2 - 2y2) - yz[-(3x2 - 2y2)] + 5zx(3x2 - 2y2)
= xy(3x2 - 2y2) + yz(3x2 - 2y2) + 5zx(3x2 - 2y2)
= (3x2 - 2y2)(xy + yz + 5zx).
Hence, xy(3x2 - 2y2) - yz(2y2 - 3x2) + zx(15x2 - 10y2) = (3x2 - 2y2)(xy + yz + 5zx).
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