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Mathematics

4x2+14x226x+32x4x^2 + \dfrac{1}{4x^2} - 2 - 6x + \dfrac{3}{2x} in the form of factors is :

  1. (2x+12x)(2x12x3)\Big(2x + \dfrac{1}{2x}\Big)\Big(2x - \dfrac{1}{2x} - 3\Big)

  2. (2x12x)(2x12x+3)\Big(2x - \dfrac{1}{2x}\Big)\Big(2x - \dfrac{1}{2x} + 3\Big)

  3. 3(2x+12x)(2x+12x3)3\Big(2x + \dfrac{1}{2x}\Big)\Big(2x + \dfrac{1}{2x} - 3\Big)

  4. (2x12x)(2x12x3)\Big(2x - \dfrac{1}{2x}\Big)\Big(2x - \dfrac{1}{2x} - 3\Big)

Factorisation

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Answer

4x2+14x226x+32x=(4x2+14x22)6x+32x=(2x12x)23(2x12x)=(2x12x)(2x12x3)\phantom{\Rightarrow} 4x^2 + \dfrac{1}{4x^2} - 2 - 6x + \dfrac{3}{2x} \\[1em] = \Big(4x^2 + \dfrac{1}{4x^2} - 2\Big) - 6x + \dfrac{3}{2x} \\[1em] = \Big(2x - \dfrac{1}{2x}\Big)^2 - 3\Big(2x - \dfrac{1}{2x}\Big) \\[1em] = \Big(2x - \dfrac{1}{2x}\Big)\Big(2x - \dfrac{1}{2x} - 3\Big)

Hence, Option 4 is the correct option.

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