Mathematics
Factorise the following:
108a2 - 3(b - c)2
Factorisation
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Answer
108a2 - 3(b - c)2
= 3[36a2 - (b - c)2]
= 3[(6a)2 - (b - c)2].
Using identity,
a2 - b2 = (a - b)(a + b).
3[(6a)2 - (b - c)2]
= 3[6a - (b - c)][6a + (b - c)]
= 3(6a - b + c)(6a + b - c).
Hence, 108a2 - 3(b - c)2 = 3(6a - b + c)(6a + b - c).
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