Factorise the following:
(2x - y)2 - 11(2x - y) + 28
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Let (2x - y) = a.
(2x - y)2 - 11(2x - y) + 28 = a2 - 11a + 28.
Factorising we get,
a2 - 11a + 28 = a2 - 7a - 4a + 28.
= a(a - 7) - 4(a - 7)
= (a - 7)(a - 4)
= (2x - y - 7)(2x - y - 4).
Hence, (2x - y)2 - 11(2x - y) + 28 = (2x - y - 7)(2x - y - 4).
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a(2a - b) - b2
(x - y)2 - 6(x - y) + 5
4(a - 1)2 - 4(a - 1) - 3
1 - 2a - 2b - 3(a + b)2.