Factorise the following:
6(x + 2y)3 + 8(x + 2y)2
49 Likes
H.C.F. of 6(x + 2y)3 and 8(x + 2y)2 is 2(x + 2y)2.
∴ 6(x + 2y)3 + 8(x + 2y)2 = 2(x + 2y)2(3(x + 2y) + 4) = 2(x + 2y)2(3x + 6y + 4).
Answered By
27 Likes
15a(2p - 3q) - 10b(2p - 3q)
3a(x2 + y2) + 6b(x2 + y2).
14(a - 3b)3 - 21p(a - 3b)
10a(2p + q)3 - 15b(2p + q)2 + 35(2p + q)