Factorise the following: 9x 3 y + 41x 2 y 2 + 20xy 3

9x 3 y + 41x 2 y 2 + 20xy 3 = xy(9x 2 + 41xy + 20y 2 ) = xy(9x 2 + 36xy + 5xy + 20y 2 ) = xy[9x(x + 4y) + 5y(x + 4y)] = xy(x + 4y)(9x + 5y). Hence, 9x 3 y + 41x 2 y 2 + 20xy 3 = xy(x + 4y)(9x + 5y).

Mathematics

Factorise the following:
9x³y + 41x²y² + 20xy³

Factorisation

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Answer

9x³y + 41x²y² + 20xy³ = xy(9x² + 41xy + 20y²)

= xy(9x² + 36xy + 5xy + 20y²)

= xy[9x(x + 4y) + 5y(x + 4y)]

= xy(x + 4y)(9x + 5y).

Hence, 9x³y + 41x²y² + 20xy³ = xy(x + 4y)(9x + 5y).

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Mathematics

Factorise the following:
9x³y + 41x²y² + 20xy³

Factorisation

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Factorise the following:9x3y + 41x2y2 + 20xy3

Factorisation

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