Factorise :
x2 + y2 + x + y + 2xy
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Given,
= x2 + y2 + 2xy + x + y
= (x + y)2 + (x + y)
= (x + y)(x + y + 1).
Hence, x2 + y2 + x + y + 2xy = (x + y)(x + y + 1).
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