By factorising x2 - 22x + 117, evaluate: (x2 - 22x + 117) ÷ (x - 13).

(x2 - 22x + 117) ÷ (x - 13) = (x2 - 13x - 9x + 117) ÷ (x - 13) = [x(x - 13) - 9(x - 13)] ÷ (x - 13) = (x - 13)(x - 9) ÷ (x - 13) = (x - 9) Hence, (x2 - 22x + 117) ÷ (x - 13) = (x - 9).

Mathematics

By factorising x² - 22x + 117, evaluate:
(x² - 22x + 117) ÷ (x - 13).

Factorisation

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Answer

(x² - 22x + 117) ÷ (x - 13)

= (x² - 13x - 9x + 117) ÷ (x - 13)

= [x(x - 13) - 9(x - 13)] ÷ (x - 13)

= (x - 13)(x - 9) ÷ (x - 13)

= (x - 9)

Hence, (x² - 22x + 117) ÷ (x - 13) = (x - 9).

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Mathematics

By factorising x² - 22x + 117, evaluate:
(x² - 22x + 117) ÷ (x - 13).

Factorisation

Answer

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Mathematics

By factorising x2 - 22x + 117, evaluate:(x2 - 22x + 117) ÷ (x - 13).

Factorisation

Answer

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By factorising x² - 22x + 117, evaluate:
(x² - 22x + 117) ÷ (x - 13).

Factorise :
$(a^2 + 3a - 5) (a^2 + 3a + 2) + 6$

Factorise :
$50x^2 - 2(x - 2)^2$

Evaluate :
(a - b)³ + (b - c)³ + (c - a)³ by writing answer in factors form.

Evaluate and write the answer in factors form :
(3a - 2b)³ + (2b - 5c)³ + (5c - 3a)³