Factorize :
x2+1x2−2−3x+3xx^2 + \dfrac{1}{x^2} - 2 - 3x + \dfrac{3}{x}x2+x21−2−3x+x3
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Given,
⇒x2+1x2−2−3x+3x⇒(x−1x)2−3(x−1x)⇒(x−1x)[(x−1x)−3]⇒(x−1x)(x−1x−3)\Rightarrow x^2 + \dfrac{1}{x^2} - 2 - 3x + \dfrac{3}{x} \\[1em] \Rightarrow \Big(x - \dfrac{1}{x}\Big)^2 - 3\Big(x - \dfrac{1}{x}\Big) \\[1em] \Rightarrow \Big(x - \dfrac{1}{x}\Big)\Big[\Big(x - \dfrac{1}{x}\Big) - 3\Big] \\[1em] \Rightarrow \Big(x - \dfrac{1}{x}\Big)\Big(x - \dfrac{1}{x} - 3\Big)⇒x2+x21−2−3x+x3⇒(x−x1)2−3(x−x1)⇒(x−x1)[(x−x1)−3]⇒(x−x1)(x−x1−3)
Hence, x2+1x2−2−3x+3x=(x−1x)(x−1x−3)x^2 + \dfrac{1}{x^2} - 2 - 3x + \dfrac{3}{x} = \Big(x - \dfrac{1}{x}\Big)\Big(x - \dfrac{1}{x} - 3\Big)x2+x21−2−3x+x3=(x−x1)(x−x1−3).
Answered By
ab(x2 + 1) + x(a2 + b2)
a3 + ab(1 - 2a) - 2b2
Factorize:
x2 - 49
25x2 - 64y2
