In a family of 3 children, the probability of having at least one boy is: 1. 2. 3. 4.

Question

KnowledgeBoat · Accepted Answer

The sample space is: {BBB, BBG, BGB, GBB, BGG, GBG, GGB, GGG} The total number of possible combinations = 8 Let E be the event of having at least one boy, then E = {BBB, BBG, BGB, GBB, BGG, GBG, GGB} The number of favorable outcomes to the event E = 7 P(E) = Hence, option 4 is the correct option.

Mathematics

In a family of 3 children, the probability of having at least one boy is: 1. 2. 3. 4.

Probability

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