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Mathematics

Find 5 geometric means between 1 and 27.

AP GP

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Answer

Let a, b, c and d be the 5 geometric means 1 and 27.

∴ 1, a, b, c, d, e and 27 are in G.P.

So, first term (a) = 1 and seventh term = 27.

Let common ratio be r.

∴ ar6 = 27

⇒ (1)r6 = 27

⇒ r6 = 33

⇒ r6 = (3)6(\sqrt{3})^6

⇒ r = 3\sqrt{3}.

Second term = ar = 1×3=31 \times \sqrt{3} = \sqrt{3},

Third term = ar2 = 1×(3)2=31 \times (\sqrt{3})^2 = 3,

Fourth term = ar3 = 1×(3)3=331 \times (\sqrt{3})^3 = 3\sqrt{3},

Fifth term = ar4 = 1×(3)4=91 \times (\sqrt{3})^4 = 9,

Sixth term = ar5 = 1×(3)5=931 \times (\sqrt{3})^5 = 9\sqrt{3}.

Hence, 5 geometric means between 1 and 27 = 3,3,33,9,93\sqrt{3}, 3, 3\sqrt{3}, 9, 9\sqrt{3}.

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