BE = CD = 50 m ED = BC = 10 m In Δ ABE, AD = AE \+ ED ⇒ AD = 50 \+ 10 m ⇒ AD = 60 m Hence, AD = 60 m.

Mathematics

Find AD, if :

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BE = CD = 50 m

ED = BC = 10 m

In Δ ABE,

$\text{tan 45°} = \dfrac{Perpendicular}{Base}\\[1em] ⇒ 1 = \dfrac{AE}{BE}\\[1em] ⇒ 1 = \dfrac{AE}{50}\\[1em] ⇒ AE = 50$

AD = AE + ED

⇒ AD = 50 + 10 m

⇒ AD = 60 m

Hence, AD = 60 m.

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