Find the additive inverse of:

$\dfrac{8}{-11}$

To find the additive inverse of any rational number, change its sign.

First express the rational number with a positive denominator.

$\dfrac{8}{-11} = \dfrac{8 \times (-1)}{-11 \times (-1)} = \dfrac{-8}{11}$

Changing the sign of $\dfrac{-8}{11}$, we get $\dfrac{8}{11}$.

[Check : $\dfrac{-8}{11} + \dfrac{8}{11} = \dfrac{0}{11} = 0$]

Hence, the additive inverse of $\mathbf{\dfrac{8}{-11} \text{ is } \dfrac{8}{11}}$.