Find (m+n)÷(m−n)(m + n) ÷ (m - n)(m+n)÷(m−n), if;
m=34m = \dfrac{3}{4}m=43 and n=43n = \dfrac{4}{3}n=34
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(m+n)÷(m−n)=(34+43)÷(34−43)(m + n) ÷ (m - n)\\[1em] = \Big(\dfrac{3}{4} + \dfrac{4}{3}\Big) ÷ \Big(\dfrac{3}{4} - \dfrac{4}{3}\Big)(m+n)÷(m−n)=(43+34)÷(43−34)
LCM of 4 and 3 is 2 x 2 x 3 = 12
=(3×34×3+4×43×4)÷(3×34×3−4×43×4)=(912+1612)÷(912−1612)=(9+1612)÷(9−1612)=(2512)÷(−712)=2512×12−7=25×1212×−7=−30084=−257= \Big(\dfrac{3 \times 3}{4 \times 3} + \dfrac{4 \times 4}{3 \times 4}\Big) ÷ \Big(\dfrac{3 \times 3}{4 \times 3} - \dfrac{4 \times 4}{3 \times 4}\Big)\\[1em] = \Big(\dfrac{9}{12} + \dfrac{16}{12}\Big) ÷ \Big(\dfrac{9}{12} - \dfrac{16}{12}\Big)\\[1em] = \Big(\dfrac{9 + 16}{12}\Big) ÷ \Big(\dfrac{9 - 16}{12}\Big)\\[1em] = \Big(\dfrac{25}{12}\Big) ÷ \Big(\dfrac{-7}{12}\Big)\\[1em] = \dfrac{25}{12} \times \dfrac{12}{-7}\\[1em] = \dfrac{25 \times 12}{12 \times -7}\\[1em] = -\dfrac{300}{84}\\[1em] = -\dfrac{25}{7}=(4×33×3+3×44×4)÷(4×33×3−3×44×4)=(129+1216)÷(129−1216)=(129+16)÷(129−16)=(1225)÷(12−7)=1225×−712=12×−725×12=−84300=−725
If mmm = 34\dfrac{3}{4}43 and nnn = 43\dfrac{4}{3}34 then (m+n)÷(m−n)=−257(m + n) ÷ (m - n) = -\dfrac{25}{7}(m+n)÷(m−n)=−725.
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Divide the sum of 37\dfrac{3}{7}73 and −514\dfrac{-5}{14}14−5 by −12-\dfrac{1}{2}−21.
m=23m = \dfrac{2}{3}m=32 and n=32n = \dfrac{3}{2}n=23
m=45m = \dfrac{4}{5}m=54 and n=−310n = -\dfrac{3}{10}n=−103
The product of two rational numbers is -5. If one of these numbers is −715\dfrac{-7}{15}15−7, find the other.
