Find (m+n)÷(m−n)(m + n) ÷ (m - n)(m+n)÷(m−n), if;
m=23m = \dfrac{2}{3}m=32 and n=32n = \dfrac{3}{2}n=23
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(m+n)÷(m−n)=(23+32)÷(23−32)(m + n) ÷ (m - n)\\[1em] = \Big(\dfrac{2}{3} + \dfrac{3}{2}\Big) ÷ \Big(\dfrac{2}{3} - \dfrac{3}{2}\Big)(m+n)÷(m−n)=(32+23)÷(32−23)
LCM of 3 and 2 is 2 x 3 = 6
=(2×23×2+3×32×3)÷(2×23×2−3×32×3)=(46+96)÷(46−96)=(4+96)÷(4−96)=(136)÷(−56)=136×6−5=13×66×−5=−7830=−135= \Big(\dfrac{2 \times 2}{3 \times 2} + \dfrac{3 \times 3}{2 \times 3}\Big) ÷ \Big(\dfrac{2 \times 2}{3 \times 2} - \dfrac{3 \times 3}{2 \times 3}\Big)\\[1em] = \Big(\dfrac{4}{6} + \dfrac{9}{6}\Big) ÷ \Big(\dfrac{4}{6} - \dfrac{9}{6}\Big)\\[1em] = \Big(\dfrac{4 + 9}{6}\Big) ÷ \Big(\dfrac{4 - 9}{6}\Big)\\[1em] = \Big(\dfrac{13}{6}\Big) ÷ \Big(\dfrac{-5}{6}\Big)\\[1em] = \dfrac{13}{6} \times \dfrac{6}{-5}\\[1em] = \dfrac{13 \times 6}{6 \times -5}\\[1em] = -\dfrac{78}{30}\\[1em] = -\dfrac{13}{5}=(3×22×2+2×33×3)÷(3×22×2−2×33×3)=(64+69)÷(64−69)=(64+9)÷(64−9)=(613)÷(6−5)=613×−56=6×−513×6=−3078=−513
If mmm = 23\dfrac{2}{3}32 and nnn = 32\dfrac{3}{2}23 then (m+n)÷(m−n)=−135(m + n) ÷ (m - n) = -\dfrac{13}{5}(m+n)÷(m−n)=−513.
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Cost of 3253\dfrac{2}{5}352 metre of cloth is ₹ 881288\dfrac{1}{2}8821. What is the cost of 1 metre of cloth?
Divide the sum of 37\dfrac{3}{7}73 and −514\dfrac{-5}{14}14−5 by −12-\dfrac{1}{2}−21.
m=34m = \dfrac{3}{4}m=43 and n=43n = \dfrac{4}{3}n=34
m=45m = \dfrac{4}{5}m=54 and n=−310n = -\dfrac{3}{10}n=−103
