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Mathematics

Find the image of the following points as directed.

(i) Point A(4, 5) reflected in the line x = 6.

(ii) Point B(-3, 2) reflected in the line x = -5.

(iii) Point C(3, 6) reflected in the line y = -2.

(iv) Point D(-2, -5) reflected in the line y = 5.

Reflection

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Answer

(i) Since, x = 6 is a straight line parallel to y-axis and at a distance of 6 units from it, therefore in the figure, PQ represents x = 6.

Steps of construction :

  1. Mark A(4, 5)on the graph.

  2. From point A draw a straight line perpendicular to PQ and produce.

  3. On this line mark a point A' which is at same distance behind PQ as A(4, 5) before it.

The graph is shown below:

Find the image of the following points as directed. Reflection, RSA Mathematics Solutions ICSE Class 10.

From graph,

A' = (8, 5).

Hence, co-ordinates of A' = (8, 5).

(ii) Since, x = -5 is a straight line parallel to y-axis and at a distance of 5 units from it, therefore in the figure, PQ represents x = -5.

Steps of construction :

  1. Mark B(-3, 2)on the graph.

  2. From point B draw a straight line perpendicular to PQ and produce.

  3. On this line mark a point B' which is at same distance behind PQ as B(-3, 2) before it.

The graph is shown below:

Find the image of the following points as directed. Reflection, RSA Mathematics Solutions ICSE Class 10.

From graph,

B' = (-7, 2).

Hence, co-ordinates of B' = (-7, 2).

(iii) Since, y = -2 is a straight line parallel to x-axis and at a distance of 2 units from it, therefore in the figure, PQ represents y = -2.

Steps of construction :

  1. Mark C(3, 6)on the graph.

  2. From point C draw a straight line perpendicular to PQ and produce.

  3. On this line mark a point C' which is at same distance behind PQ as C(3, 6) before it.

The graph is shown below:

Find the image of the following points as directed. Reflection, RSA Mathematics Solutions ICSE Class 10.

From graph,

C' = (3, -10).

Hence, co-ordinates of C' = (3, -10).

(iv) Since, y = 5 is a straight line parallel to x-axis and at a distance of 5 units from it, therefore in the figure, PQ represents y = 5.

Steps of construction :

  1. Mark D(-2, -5)on the graph.

  2. From point D draw a straight line perpendicular to PQ and produce.

  3. On this line mark a point D' which is at same distance behind PQ as D(-2, -5) before it.

The graph is shown below:

Find the image of the following points as directed. Reflection, RSA Mathematics Solutions ICSE Class 10.

From graph,

D' = (-2, 15).

Hence, co-ordinates of D' = (-2, 15).

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