Find median for the following data :

50	59	27	78	54	72
58	57	31	65	42	60
22	37	40	and	28

On arranging the given set of data in ascending order of magnitude, we get: 22, 27, 28, 31, 37, 40, 42, 50, 54, 57, 58, 59, 60, 65, 72 and 78.

Number of observations, n = 16 (even)

$\text{Median} = \dfrac{\Big(\dfrac{n}{2}\Big)^{th}\text{ term} + \Big(\dfrac{n}{2} + 1\Big)^{th}\text{ term}}{2}\\[1em] \dfrac{\Big(\dfrac{16}{2}\Big)^{th} \text{ term}+ \Big(\dfrac{16}{2} + 1\Big)^{th}\text{ term}}{2}\\[1em] = \dfrac{8^{th}\text{ term} + (8 + 1)^{th}\text{ term}}{2}\\[1em] = \dfrac{8^{th}\text{ term} + 9^{th}\text{ term}}{2}\\[1em] = \dfrac{50 + 54}{2}\\[1em] = \dfrac{104}{2}\\[1em] = 52$

Hence, Median = 52.