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Mathematics

Find the product :

−9×718-9 \times \dfrac{7}{18}

Rational Numbers

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Answer

The product of two rational numbers ab and cd\dfrac{a}{b} \text{ and } \dfrac{c}{d} is given by ab×cd=a×cb×d\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}.

Multiplying,

−9×718=−91×718=(−9)×71×18=−6318=−72=−312-9 \times \dfrac{7}{18} = \dfrac{-9}{1} \times \dfrac{7}{18} \\[1em] = \dfrac{(-9) \times 7}{1 \times 18} \\[1em] = \dfrac{-63}{18} = \dfrac{-7}{2} \\[1em] = -3\dfrac{1}{2}

Hence, −9×718=−312\mathbf{-9 \times \dfrac{7}{18} = -3\dfrac{1}{2}}.

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