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Mathematics

Find the product :

49×712\dfrac{4}{9} \times \dfrac{7}{12}

Rational Numbers

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Answer

The product of two rational numbers ab and cd\dfrac{a}{b} \text{ and } \dfrac{c}{d} is given by ab×cd=a×cb×d\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}.

Multiplying,

49×712=4×79×12=28108=727\dfrac{4}{9} \times \dfrac{7}{12} = \dfrac{4 \times 7}{9 \times 12} \\[1em] = \dfrac{28}{108} \\[1em] = \dfrac{7}{27}

Hence, 49×712=727\mathbf{\dfrac{4}{9} \times \dfrac{7}{12} = \dfrac{7}{27}}.

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