Find the product :

$\dfrac{-3}{16} \times \dfrac{8}{-15}$

The product of two rational numbers $\dfrac{a}{b} \text{ and } \dfrac{c}{d}$ is given by $\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}$.

Multiplying,

$\dfrac{-3}{16} \times \dfrac{8}{-15} = \dfrac{(-3) \times 8}{16 \times (-15)} \\[1em] = \dfrac{-24}{-240} \\[1em] = \dfrac{1}{10}$

Hence, $\mathbf{\dfrac{-3}{16} \times \dfrac{8}{-15} = \dfrac{1}{10}}$.