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Mathematics

Find nn so that 811÷85=83×82n18^{11} ÷ 8^5 = 8^{-3} \times 8^{2n-1}.

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811÷85=83×82n18115=83+(2n1)86=83+2n186=84+2n6=4+2n6+4=2n10=2nn=102n=58^{11} ÷ 8^5 = 8^{-3} \times 8^{2n-1}\\[1em] \Rightarrow 8^{11 - 5} = 8^{-3 + (2n-1)}\\[1em] \Rightarrow 8^{6} = 8^{-3 + 2n - 1}\\[1em] \Rightarrow 8^{6} = 8^{-4 + 2n}\\[1em] \Rightarrow 6 = -4 + 2n\\[1em] \Rightarrow 6 + 4 = 2n\\[1em] \Rightarrow 10 = 2n\\[1em] \Rightarrow n = \dfrac{10}{2} \\[1em] \Rightarrow n = 5

If 811÷85=83×82n18^{11} ÷ 8^5 = 8^{-3} \times 8^{2n-1}, then n=5n = 5.

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