Mathematics
Find the sum of the greatest and the smallest 6-digit numbers formed by the digits 2, 0, 4, 7, 6, 5 using each digit only once.
Answer
The given digits are 2, 0, 4, 7, 6 and 5, and each digit is used only once.
For the greatest 6-digit number, arrange the digits in descending order: 7, 6, 5, 4, 2, 0.
Greatest 6-digit number = 7,65,420.
For the smallest 6-digit number, the lakh's place cannot be 0. So, place the smallest non-zero digit (2) at the lakh's place, then arrange the remaining digits (0, 4, 5, 6, 7) in ascending order.
Smallest 6-digit number = 2,04,567.
Sum = 7,65,420 + 2,04,567
= 9,69,987
Hence, the sum of the greatest and the smallest 6-digit numbers is 9,69,987.
Related Questions
Write the smallest eight-digit number using four different digits.
Find the difference between the greatest and the smallest 4-digit numbers formed by the digits 0, 3, 6, 9
Find the sum of the four-digit greatest number and the five-digit smallest number, each number having three different digits.
Write the greatest and the smallest four-digit numbers using four different digits with the conditions:
(i) Digit 3 always at hundred's place.
(ii) Digit 0 always at ten's place.