Find the cube of $\dfrac{3}{7}$

$\Big(\dfrac{3}{7}\Big)^3\\[1em] = \Big(\dfrac{3}{7} \times \dfrac{3}{7} \times \dfrac{3}{7}\Big)\\[1em] = \dfrac{27}{343}$

$\Big(\dfrac{3}{7}\Big)^3 = \dfrac{27}{343}$