Find the cube of 89\dfrac{8}{9}98
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(89)3=(89×89×89)=512729\Big(\dfrac{8}{9}\Big)^3\\[1em] = \Big(\dfrac{8}{9} \times \dfrac{8}{9} \times \dfrac{8}{9}\Big)\\[1em] = \dfrac{512}{729}(98)3=(98×98×98)=729512
(89)3=512729\Big(\dfrac{8}{9}\Big)^3 = \dfrac{512}{729}(98)3=729512
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