Find the cube-roots of -216 x 1728

Prime factors of 216:

Finding prime factors of 1728:

$\sqrt[3]{-216 \times 1728}\\[1em] = \sqrt[3]{-216} \times \sqrt[3]{1728}\\[1em] = -\sqrt[3]{(2 \times 2 \times 2) \times (3 \times 3 \times 3)} \times \sqrt[3]{(2 \times 2 \times 2) \times (2 \times 2 \times 2) \times (3 \times 3 \times 3)}\\[1em] = -(2 \times 3) \times (2 \times 2 \times 3)\\[1em] = -6 \times 12\\[1em] = -72$

$\sqrt[3]{-216 \times 1728} = -72$