Find the cube-roots of 700 x 2 x 49 x 5
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700×2×49×53=7×49×100×2×53=(7×7×7)×(2×2×2)×(5×5×5)3=7×2×5=70\sqrt[3]{700 \times 2 \times 49 \times 5}\\[1em] = \sqrt[3]{7 \times 49 \times 100 \times 2 \times 5}\\[1em] = \sqrt[3]{(7 \times 7 \times 7) \times (2 \times 2 \times 2) \times (5 \times 5 \times 5)}\\[1em] = 7 \times 2 \times 5\\[1em] = 703700×2×49×5=37×49×100×2×5=3(7×7×7)×(2×2×2)×(5×5×5)=7×2×5=70
700×2×49×53=70\sqrt[3]{700 \times 2 \times 49 \times 5} = 703700×2×49×5=70
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