Predict the output:

list1 = [2, 3, 3, 2, 5,3, 2, 5, 1,1] 
counts = {}
ct = 0
lst = []
for num in list1:
  if num not in lst:
    lst.append(num)
    counts[num] = 0
  ct = ct+1
  counts[num] = counts[num]+1 
print(counts)
for key in counts.keys():
  counts[key] = key * counts[key] 
print(counts)

Create a dictionary 'ODD' of odd numbers between 1 and 10, where the key is the decimal number and the value is the corresponding number in words.
Perform the following operations on this dictionary :

1. Display the keys
2. Display the values
3. Display the items
4. Find the length of the dictionary
5. Check if 7 is present or not
6. Check if 2 is present or not
7. Retrieve the value corresponding to the key 9
8. Delete the item from the dictionary corresponding to the key 9

my_dict = {}
my_dict[(1,2,4)] = 8 
my_dict[[4,2,1]] = 10 
print(my_dict)

Predict the output:

fruit = {}
L1 = ['Apple', 'banana', 'apple'] 
for index in L1 :
  if index in fruit: 
    fruit[index] += 1
  else :
    fruit[index] = 1
print(len(fruit))
print(fruit)